(a^{2}+2a)^{2}-2(a^{2}+2a)-3 u=(a^{2}+2a) (u)^{2}-2u-3 (u+1)(u-3) (a^{2}+2a+1)(a^{2}+2a-3) WORNG ANS (a+1)(a+1)(a-1)(a+3)
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I can't see why this is wrong ((a+1)(a+1)(a-1)(a+3))... ... What is the correct ans?
Originally Posted by zbest1966 WORNG ANS (a+1)(a+1)(a-1)(a+3) I agree with Goku, this looks correct. The only other thing you could maybe do is combine the two factors of $\displaystyle a+1$: $\displaystyle (a+1)(a+1)(a-1)(a+3)$ $\displaystyle =(a+1)^2(a-1)(a+3)$
correct (a+2)(a-2)(a+1)(a-1)
Originally Posted by zbest1966 correct (a+2)(a-2)(a+1)(a-1) No, that is incorrect. You can verify this by substituting values for $\displaystyle a$. Your original answer was the right one.
Originally Posted by zbest1966 (a^{2}+2a)^{2}-2(a^{2}+2a)-3 u=(a^{2}+2a) (u)^{2}-2u-3 (u+1)(u-3) (a^{2}+2a+1)(a^{2}+2a-3) You're on the right track. Now all you need to do is factor those two expresions. (a^{2}+2a+1) = (a+1)(a+1) (a^{2}+2a-3) = (a+3)(a-1)
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