(a2+1)2-7(a2+1)+10
ans = Its wrong I tried a4-1+7a2+16
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(a2+1)2-7(a2+1)+10
ans = Its wrong I tried a4-1+7a2+16
There are no radicals here. Did you make a mistake when typing the problem?Quote:
Originally Posted by zbest1966
Anyway, this is a quadratic in form. Let. Then
.
Now factor that trinomial on the right, and then substitute forto get everything back in terms of
.
a^4 + 1-7a^2-7+10
a^4-6-7a^2+10
a^4-7a^2+4
Im stuck
Did you not read what I wrote? We have a quadratic inQuote:
Originally Posted by zbest1966
. You don't need to multiply everything out. And if you were to multiply everything out, you're doing it wrong:
.
I've shown you how to reduce the problem to factoring. Can you factor this trinomial?