a) 2(-3a^{2}b)^{2}=2 x (-3)^{2} x (a^{2})^{2} x (b)^{2} = 2 x 9 x a^{4} x b^{2} = 18a^{4}b^{2}
b)2b^{n} x 2^{3}b = 2 x 2^{3} x b^{n} x b = 2^{4} x b^{n+1} = 16b^{n+1 anyways I would always say to practice these sorts of exercises with the formulas that Reckoner gave here.}
It is letter A. Is this really a grade 9 equation?
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