I've been having trouble with this equation for a little while. I cannot get the answer that's in the answer key and have no idea where I'm going wrong. If someone could please show their calculations I'd really appreciate it.
I've been having trouble with this equation for a little while. I cannot get the answer that's in the answer key and have no idea where I'm going wrong. If someone could please show their calculations I'd really appreciate it.
$\displaystyle \frac{7}{x+2}-\frac{x+8}{4-x^2}+\frac{3x-2}{4-4x+x^2}$
$\displaystyle \frac{7}{x+2}-\frac{x+8}{(2-x)(2+x)}+\frac{3x-2}{(x-2)^2}$
$\displaystyle \frac{7}{x+2}+\frac{x+8}{(x-2)(x+2)}+\frac{3x-2}{(x-2)^2}$
$\displaystyle \frac{7(x-2)^2}{(x-2)^2(x+2)}+\frac{(x+8)(x-2)}{(x-2)^2(x+2)}+\frac{(3x-2)(x+2)}{(x-2)^2(x+2)}$
$\displaystyle \frac{7(x-2)^2 + (x+8)(x-2) + (3x-2)(x+2)}{(x-2)^2(x+2)}$
can you finish from here?