2(a+b)^{2 }+ 5(a + b) - 3
ans [(2(a + b) + 1)][(a + b) + 3]
Hello, zbest1966!
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2(a+b)^{2} + 5(a + b) - 3
ans: [(2(a + b) + 1)][(a + b) + 3] . . . . This is wrong.
$\displaystyle \big[2(a+b) + 1\big]\big[(a+b)+3)\big] \;=\;(a+b)^2 + {\color{red}7}(a+b)\,{\color{red}+}\,3$
The correct factoring is: .$\displaystyle \big[2(a+b) - 1\big]\big[(a+b) + 3\big]$