factoring

**zbest1966** · June 4th 2012, 08:13 PM

2(a+b)²+ 5(a + b) - 3

ans [(2(a + b) + 1)][(a + b) + 3]

**Soroban** · June 4th 2012, 08:38 PM

Hello, zbest1966!

There's something wrong with the problem.
Please check for typos.

2(a+b)² + 5(a + b) - 3

ans: [(2(a + b) + 1)][(a + b) + 3] . . . . This is wrong.

$\big[2(a+b) + 1\big]\big[(a+b)+3)\big] \;=\;(a+b)^2 + {\color{red}7}(a+b)\,{\color{red}+}\,3$

The correct factoring is: . $\big[2(a+b) - 1\big]\big[(a+b) + 3\big]$

**highvoltage** · June 4th 2012, 08:43 PM

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