# factoring

• Jun 4th 2012, 07:13 PM
zbest1966
factoring
2(a+b)2 + 5(a + b) - 3

ans [(2(a + b) + 1)][(a + b) + 3]
• Jun 4th 2012, 07:38 PM
Soroban
Re: factoring
Hello, zbest1966!

There's something wrong with the problem.

Quote:

2(a+b)2 + 5(a + b) - 3

ans: [(2(a + b) + 1)][(a + b) + 3] . . . . This is wrong.

$\big[2(a+b) + 1\big]\big[(a+b)+3)\big] \;=\;(a+b)^2 + {\color{red}7}(a+b)\,{\color{red}+}\,3$

The correct factoring is: . $\big[2(a+b) - 1\big]\big[(a+b) + 3\big]$

• Jun 4th 2012, 07:43 PM
highvoltage
Re: factoring