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Math Help - Multipling radicands

  1. #1
    Member purplec16's Avatar
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    Multipling radicands

    sqrt{-25}*sqrt{-4}
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  2. #2
    MHF Contributor Reckoner's Avatar
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    Re: Multipling radicands

    Quote Originally Posted by purplec16 View Post
    sqrt{-25}*sqrt{-4}
    Note that the familiar property, \sqrt a\sqrt b = \sqrt{ab} applies only to nonnegative a and b. Instead, we have

    \sqrt{-25}\sqrt{-4}

    =\left(i\sqrt{25}\right)\left(i\sqrt4\right)

    =(5i)(2i) = 10i^2.

    Now, what is i^2? Simplify.
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  3. #3
    Member purplec16's Avatar
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    Re: Multipling radicands

    =-10
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  4. #4
    Member purplec16's Avatar
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    Re: Multipling radicands

    What do you wrap the latex in? I am for some reason unable to do it/ find it?
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  5. #5
    MHF Contributor Reckoner's Avatar
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    Re: Multipling radicands

    Quote Originally Posted by purplec16 View Post
    What do you wrap the latex in? I am for some reason unable to do it/ find it?
    Enclose your LaTeX in [tex] and [/tex] tags. For example,

    [tex]\sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}6[/tex]

    yields

    \sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}6


    Your answer is correct, by the way.
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  6. #6
    Member purplec16's Avatar
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    Re: Multipling radicands

    Thank you!!!
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