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Math Help - Simplify

  1. #1
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    Simplify

    (c+1/c2)2

    = (c+1/c)(c+1/c)

    = c2+1/c2+1/c2+1/c4

    =c2+2/c2+1/c4

    =c6+2c2+1
    Last edited by zbest1966; June 2nd 2012 at 08:36 PM.
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  2. #2
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    Re: Simplify

    Are you just wanting someone to double check your work?
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  3. #3
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    Re: Simplify

    Quote Originally Posted by zbest1966 View Post
    (c+1/c2)2

    = (c+1/c)(c+1/c)

    = c2+1/c2+1/c2+1/c4

    =c2+2/c2+1/c4

    =c6+2c2+1
    I suggest you double check your question. Are you trying to expand \displaystyle \begin{align*} \left(c + \frac{1}{c}\right)^2 \end{align*} or \displaystyle \begin{align*} \left(c + \frac{1}{c^2}\right)^2 \end{align*} ?
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  4. #4
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    Re: Simplify

    Hello, zbest1966!

    Wow! . . . Can you make a few more errors ... please?


    \left(c+\frac{1}{c^2}\right)^2

    . . =\;\left(c+\frac{1}{c}\right)\left(c+\frac{1}{c} \right) . Where is the {\color{blue}c^2}?

    . . =\; c^2 + \frac{1}{c^2}+\frac{1}{c^2} +\frac{1}{c^4} . This is terribly wrong!

    . . =\; c^2 + \frac{2}{c^2} +\frac{1}{c^4} . Well, you added correctly ...

    . . =\; c^6 + 2c^2 +1 . What happened to the denominator?

    I will assume that the problem is: . \left(c + \frac{1}{c^2}\right)^2

    We have: . \left(c + \frac{1}{c^2}\right)\left(c + \frac{1}{c^2}\right)

    "FOIL": . (c)(c) + (c)\left(\frac{1}{c^2}\right) + \left(\frac{1}{c^2}\right)(c) + \left(\frac{1}{c^2}\right)\left(\frac{1}{c^2} \right)

    . . . . . =\;c^2 + \frac{1}{c} + \frac{1}{c} + \frac{1}{c^4}

    . . . . . =\;c^2 + \frac{2}{c} + \frac{1}{c^4}

    . . . . . =\;\frac{c^6 + 2c^3 + 1}{c^4}
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  5. #5
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    Re: Simplify

    Last edited by Wilmer; June 3rd 2012 at 07:05 AM.
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