algebria expression

**zbest1966** · June 2nd 2012, 03:15 PM

1. x^3/2( $\sqrt{x}$ - 1/ $\sqrt{x}x<sup>2</sup>$ )

Made a attempt

x^3/4 - x^3/4/x

= x^3/2. x^1/2 - x^3/2/ (x^1/2. x^3/2)

= x²-x^3/2/x²

= 1-x^1/2

**Plato** · June 2nd 2012, 03:34 PM

Originally Posted by zbest1966

1. x^3/2(sqrt x - 1 sqrt x)
How does some make the sqrt symbols?

Use LaTeX code. On the tool bar the $\Sigma$ gives [TEX][/TEX] as a wrap.

[TEX]\sqrt{3x^2+\sin^2(2x)}[/TEX] gives $\sqrt{3x^2+\sin^2(2x)}$ .

**Wilmer** · June 2nd 2012, 04:32 PM

Hint: x^3/2) = xSQRT(x)

**Reckoner** · June 2nd 2012, 04:43 PM

Originally Posted by zbest1966

1. x^3/2( $\sqrt{x}$ - 1/ $\sqrt{x}$ )

Made a attempt

x^3/4 - x^3/4/x

I think you're multiplying exponents when you should be adding. Try again, using these properties of exponents:

$a^ma^n = a^{m+n}$

$\frac{a^m}{a^n} = a^{m-n}$

$a^{-n} = \frac1{a^n}$

$a^{m/n} = \sqrt[n]{a^m}$

So, for example, $x^{3/2}\cdot x^{1/2}=x^2$ .

**Plato** · June 2nd 2012, 04:56 PM

Originally Posted by Wilmer

Hint: x^3/2) = xSQRT(x)

@Wilmer if you want to really help, then why do you not learn LaTeX coding?
It really is so simple and most helpful!

**Wilmer** · June 2nd 2012, 07:10 PM

x*SQRT(x)*[SQRT(x) - 1/SQRT(x)]
= x^2 - x
= x(x - 1)

LATEX version in the near(?) future...

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