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Math Help - algebria expression

  1. #1
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    algebria expression

    1. x3/2( \sqrt{x} - 1/ \sqrt{x}x<sup>2</sup>)

    Made a attempt

    x3/4 - x 3/4/x

    = x3/2. x1/2 - x3/2/ (x1/2. x3/2)

    = x2-x3/2/x2

    = 1-x1/2
    Last edited by zbest1966; June 2nd 2012 at 07:58 PM.
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  2. #2
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    Re: algebria expression

    Quote Originally Posted by zbest1966 View Post
    1. x3/2(sqrt x - 1 sqrt x)
    How does some make the sqrt symbols?
    Use LaTeX code. On the tool bar the \Sigma gives [TEX][/TEX] as a wrap.

    [TEX]\sqrt{3x^2+\sin^2(2x)}[/TEX] gives \sqrt{3x^2+\sin^2(2x)}.
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  3. #3
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    Re: algebria expression

    Hint: x^3/2) = xSQRT(x)
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  4. #4
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    Re: algebria expression

    Quote Originally Posted by zbest1966 View Post
    1. x3/2( \sqrt{x} - 1/ \sqrt{x})

    Made a attempt

    x3/4 - x 3/4/x
    I think you're multiplying exponents when you should be adding. Try again, using these properties of exponents:

    a^ma^n = a^{m+n}

    \frac{a^m}{a^n} = a^{m-n}

    a^{-n} = \frac1{a^n}

    a^{m/n} = \sqrt[n]{a^m}

    So, for example, x^{3/2}\cdot x^{1/2}=x^2.
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  5. #5
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    Re: algebria expression

    Quote Originally Posted by Wilmer View Post
    Hint: x^3/2) = xSQRT(x)
    @Wilmer if you want to really help, then why do you not learn LaTeX coding?
    It really is so simple and most helpful!
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  6. #6
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    Re: algebria expression

    x*SQRT(x)*[SQRT(x) - 1/SQRT(x)]
    = x^2 - x
    = x(x - 1)

    LATEX version in the near(?) future...
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