# algebria expression

• Jun 2nd 2012, 03:15 PM
zbest1966
algebria expression
1. x3/2($\displaystyle \sqrt{x}$ - 1/ $\displaystyle \sqrt{x}x2$)

x3/4 - x 3/4/x

= x3/2. x1/2 - x3/2/ (x1/2. x3/2)

= x2-x3/2/x2

= 1-x1/2
• Jun 2nd 2012, 03:34 PM
Plato
Re: algebria expression
Quote:

Originally Posted by zbest1966
1. x3/2(sqrt x - 1 sqrt x)
How does some make the sqrt symbols?

Use LaTeX code. On the tool bar the $\displaystyle \Sigma$ gives [TEX][/TEX] as a wrap.

[TEX]\sqrt{3x^2+\sin^2(2x)}[/TEX] gives $\displaystyle \sqrt{3x^2+\sin^2(2x)}$.
• Jun 2nd 2012, 04:32 PM
Wilmer
Re: algebria expression
Hint: x^3/2) = xSQRT(x)
• Jun 2nd 2012, 04:43 PM
Reckoner
Re: algebria expression
Quote:

Originally Posted by zbest1966
1. x3/2($\displaystyle \sqrt{x}$ - 1/ $\displaystyle \sqrt{x}$)

x3/4 - x 3/4/x

I think you're multiplying exponents when you should be adding. Try again, using these properties of exponents:

$\displaystyle a^ma^n = a^{m+n}$

$\displaystyle \frac{a^m}{a^n} = a^{m-n}$

$\displaystyle a^{-n} = \frac1{a^n}$

$\displaystyle a^{m/n} = \sqrt[n]{a^m}$

So, for example, $\displaystyle x^{3/2}\cdot x^{1/2}=x^2$.
• Jun 2nd 2012, 04:56 PM
Plato
Re: algebria expression
Quote:

Originally Posted by Wilmer
Hint: x^3/2) = xSQRT(x)

@Wilmer if you want to really help, then why do you not learn LaTeX coding?
It really is so simple and most helpful!
• Jun 2nd 2012, 07:10 PM
Wilmer
Re: algebria expression
x*SQRT(x)*[SQRT(x) - 1/SQRT(x)]
= x^2 - x
= x(x - 1)

LATEX version in the near(?) future...