1. x^{3/2}($\displaystyle \sqrt{x}$ - 1/ $\displaystyle \sqrt{x}x^{2}$)

Made a attempt

x^{3/4}- x^{ 3/4}/x

= x^{3/2}. x^{1/2}- x^{3/2}/ (x^{1/2}. x^{3/2})

= x^{2}-x^{3/2}/x^{2}

= 1-x^{1/2}

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- Jun 2nd 2012, 03:15 PMzbest1966algebria expression
1. x

^{3/2}($\displaystyle \sqrt{x}$ - 1/ $\displaystyle \sqrt{x}x^{2}$)

Made a attempt

x^{3/4}- x^{ 3/4}/x

= x^{3/2}. x^{1/2}- x^{3/2}/ (x^{1/2}. x^{3/2})

= x^{2}-x^{3/2}/x^{2}

= 1-x^{1/2} - Jun 2nd 2012, 03:34 PMPlatoRe: algebria expression
- Jun 2nd 2012, 04:32 PMWilmerRe: algebria expression
Hint: x^3/2) = xSQRT(x)

- Jun 2nd 2012, 04:43 PMReckonerRe: algebria expression
I think you're multiplying exponents when you should be adding. Try again, using these properties of exponents:

$\displaystyle a^ma^n = a^{m+n}$

$\displaystyle \frac{a^m}{a^n} = a^{m-n}$

$\displaystyle a^{-n} = \frac1{a^n}$

$\displaystyle a^{m/n} = \sqrt[n]{a^m}$

So, for example, $\displaystyle x^{3/2}\cdot x^{1/2}=x^2$. - Jun 2nd 2012, 04:56 PMPlatoRe: algebria expression
- Jun 2nd 2012, 07:10 PMWilmerRe: algebria expression
x*SQRT(x)*[SQRT(x) - 1/SQRT(x)]

= x^2 - x

= x(x - 1)

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