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Math Help - Distributive Law

  1. #1
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    Distributive Law

    Ok, so I'm self-teaching myself Algebra over the summer so that's one less math class I'll have to worry about and I have a question about 2 algebra problems. I'm trying to find out how exactly the author of the book I'm using got the answer to these 2 questions and it would help a lot if you could explain why the answers are the answers. I believe monomial's and polynomial's using the distributive law.

    The first 2x^2y(x^2-xy+3y) and the answer in the book was 2x^4y - 2x^3y^2+6x^2y^2

    The second a/2 (2a-4+3b) and the answer was a^2-2a+3ab/2
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  2. #2
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    Re: Distributive Law

    Quote Originally Posted by CSMajor View Post
    I believe monomial's and polynomial's using the distributive law.

    The first 2x^2y(x^2-xy+3y) and the answer in the book was 2x^4y - 2x^3y^2+6x^2y^2
    Do you understand how (2x^2y)(x^2)=2x^4y works?

    Do you understand how (2x^2y)(-xy)=-2x^3y^2 works?

    Do you understand how (2x^2y)(3y)=6x^2y^2 works?
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  3. #3
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    Re: Distributive Law

    Somewhat, but not really to be honest.
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    Re: Distributive Law

    Quote Originally Posted by CSMajor View Post
    Somewhat, but not really to be honest.
    Try to explain what you don't understand about each of those three.
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    Re: Distributive Law

    Well for the first and second problems I understood why you got those answers. For the third I think I understand how you got the answer, but not exactly. Unless I'm able to multiply
    3y times 2x^2 to get 6x^2y^2 that way, but I didn't think that was the right way.
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    Re: Distributive Law

    Quote Originally Posted by CSMajor View Post
    I'm able to multiply 3y times 2x^2 to get 6x^2y^2 that way, but I didn't think that was the right way.
    (2x^2y)(3y)=2\cdot 3\cdot x^2\cdot y\cdot y=6x^2y^2
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  7. #7
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    Re: Distributive Law

    yeahhh... you made it look so much easier than I made it seem written out.
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