# Thread: Election word problem

1. ## Election word problem

In an election, 2.8 million votes were cast and each vote was for either Candidate I or Candidate II. Candidate I received 28,000 more votes than Candidate II. What percent of the 2.8 million votes were case for Candidate I ?
A. 50.05%
B. 50.1%
C. 50.5%
D. 51%
E. 55%

2. ## Re: Election word problem

Let $x$ denote the number of votes Candidate I recieved. Then since he/she recieved $28.000$ votes more than Candidate II, number $x-28000$ is the number of votes Candidate II recieved. Because the total number of votes is $2.800.000$ you can form the equation:
$x+(x-28000)=2800000.$
You will find that $x=1414000$, and number represents $\frac{1414000}{2800000}=0,505=50,5\%$. So correct answer is C.

3. ## Re: Election word problem

$\frac{28000}{2.8 \, million} = \frac{2.8 \times 10^4}{2.8 \times 10^6} = 10^{-2} = 0.01 = 1$% difference of the total vote

the winner received 50.5% , the loser received 49.5%

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