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Math Help - Election word problem

  1. #1
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    Election word problem

    In an election, 2.8 million votes were cast and each vote was for either Candidate I or Candidate II. Candidate I received 28,000 more votes than Candidate II. What percent of the 2.8 million votes were case for Candidate I ?
    A. 50.05%
    B. 50.1%
    C. 50.5%
    D. 51%
    E. 55%
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  2. #2
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    Re: Election word problem

    Let x denote the number of votes Candidate I recieved. Then since he/she recieved 28.000 votes more than Candidate II, number x-28000 is the number of votes Candidate II recieved. Because the total number of votes is 2.800.000 you can form the equation:
    x+(x-28000)=2800000.
    You will find that x=1414000, and number represents \frac{1414000}{2800000}=0,505=50,5\%. So correct answer is C.
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  3. #3
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    Re: Election word problem

    \frac{28000}{2.8 \, million} = \frac{2.8 \times 10^4}{2.8 \times 10^6} = 10^{-2} = 0.01 = 1% difference of the total vote

    the winner received 50.5% , the loser received 49.5%
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