# Election word problem

• May 30th 2012, 01:06 PM
Mat724
Election word problem
In an election, 2.8 million votes were cast and each vote was for either Candidate I or Candidate II. Candidate I received 28,000 more votes than Candidate II. What percent of the 2.8 million votes were case for Candidate I ?
A. 50.05%
B. 50.1%
C. 50.5%
D. 51%
E. 55%
• May 30th 2012, 01:18 PM
MathoMan
Re: Election word problem
Let $\displaystyle x$ denote the number of votes Candidate I recieved. Then since he/she recieved $\displaystyle 28.000$ votes more than Candidate II, number $\displaystyle x-28000$ is the number of votes Candidate II recieved. Because the total number of votes is $\displaystyle 2.800.000$ you can form the equation:
$\displaystyle x+(x-28000)=2800000.$
You will find that $\displaystyle x=1414000$, and number represents $\displaystyle \frac{1414000}{2800000}=0,505=50,5\%$. So correct answer is C.
• May 30th 2012, 03:11 PM
skeeter
Re: Election word problem
$\displaystyle \frac{28000}{2.8 \, million} = \frac{2.8 \times 10^4}{2.8 \times 10^6} = 10^{-2} = 0.01 = 1$% difference of the total vote