Re: Just a simple order of operations question

Re: Just a simple order of operations question

Re: Just a simple order of operations question

Wow that is amazingly helpful. You're epic. What would happen if I ended up doing the ( ) ( ) ( ) thing depending on ^n? And would you recommend the way you did it over that method?

Also another thing. This concerns getting the lowest common denominator in order to -/+ fractions together.

For example I am confronted with this. (1/2) - (2/x+4)

The way I was taught to find the LCD was split the lower halves into their prime factors, which I thought was 2 and 2^2. Although I think I got that wrong. Can you explain to me how to properly find the LCD as my lecturer clearly fails at explaining these things.

Re: Just a simple order of operations question

Re: Just a simple order of operations question

Quote:

Originally Posted by

**Reckoner**
To find the LCD, multiply the highest power of each factor:

.

Not sure what you did/meant here

and yeah I meant 2 / (x + 4)

Re: Just a simple order of operations question

Also I figured at if we had 2 and (x + 4)...

wouldnt the factors be 2, x, 4

and then wouldnt it be 2 * x * 4, making 8x?

Re: Just a simple order of operations question

Quote:

Originally Posted by

**SplashDamage** Not sure what you did/meant here

The first denominator is:

The second:

And the third:

In all of these we have four different factors: 2, 3, , and .

So we first look for the highest power of 2. The first denominator has zero factors of 2 ( ), the second one has two factors ( ), and the third denominator has one factor ( ). In our LCD, we use the highest power of 2 among these three, so we take . Similarly, is the highest power of 3 (the other denominators have *zero* factors of three), is the highest power of , and is the highest power of . We take each of these and multiply them together.

Re: Just a simple order of operations question

OMG i get it. That makes the other question I just made clear.

Re: Just a simple order of operations question

Quote:

Originally Posted by

**SplashDamage** Also I figured at if we had 2 and (x + 4)...

wouldnt the factors be 2, x, 4

No, factors are the things that are being *multiplied* to form the final product. and 4 are being added, not multiplied. So , in its entirety, is a single factor, and cannot be split further.

Re: Just a simple order of operations question

So something like 5x can be split into 5 and x, or something like 25x could be split into 5^2 and x. And two factors can be grouped as one factor if there is parenthesis around them for example (x + 4)?

and if that parenthesis was not there, would the LCD indeed be 4x?

actually no it would still be 2 (x + 4) wouldnt it.

Re: Just a simple order of operations question

Quote:

Originally Posted by

**SplashDamage** So something like 5x can be split into 5 and x, or something like 25x could be split into 5^2 and x.

Yes

Quote:

Originally Posted by

**SplashDamage** And two factors can be grouped as one factor if there is parenthesis around them for example (x + 4)?

I'm not sure I understand what you mean. We can group factors as we please, for multiplication is associative: . is a single factor, however (though it consists of two *terms*).

Re: Just a simple order of operations question

So with or without the brackets, it would still be 2(x + 4)?

Re: Just a simple order of operations question

Quote:

Originally Posted by

**SplashDamage** So with or without the brackets, it would still be 2(x + 4)?

Right. When is by itself, we don't need to write the parentheses. But it's still a single factor, and we can't factor it further.

Re: Just a simple order of operations question

What would happen if we had (x + 8) instead? since 8 can be factored.

also if we had x + 8

Re: Just a simple order of operations question