Results 1 to 2 of 2

Thread: Algeb

  1. #1
    Member srirahulan's Avatar
    Joined
    Apr 2012
    From
    Srilanka
    Posts
    180

    Post Algeb

    if the quadratic equation$\displaystyle 2x^2-qx+r=0 $have the roots $\displaystyle (\alpha+1),(\beta+2) $find out the value of q,r in terms of b,c.$\displaystyle x^2-bx+c=0 $the quadratic equation have the real roots $\displaystyle \alpha,\beta $ and also $\displaystyle \ \alpha\geq\beta$if $\displaystyle \ \alpha=\beta$prove $\displaystyle q^2=4(2r+1) $
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    21,776
    Thanks
    2823
    Awards
    1

    Re: Algeb

    Quote Originally Posted by srirahulan View Post
    if the quadratic equation$\displaystyle 2x^2-qx+r=0 $have the roots $\displaystyle (\alpha+1),(\beta+2) $find out the value of q,r in terms of b,c.$\displaystyle x^2-bx+c=0 $the quadratic equation have the real roots $\displaystyle \alpha,\beta $ and also $\displaystyle \ \alpha\geq\beta$if $\displaystyle \ \alpha=\beta$prove $\displaystyle q^2=4(2r+1) $
    Using the product of the roots we get $\displaystyle (\alpha +1)(\beta +2)=\frac{r}{2}$ and $\displaystyle (\alpha)(\beta)=c$

    Using the sum of the roots we get $\displaystyle \alpha +\beta+3 =\frac{q}{2}$ and $\displaystyle \alpha +\beta=b$
    Last edited by Plato; May 28th 2012 at 07:39 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Algeb
    Posted in the Algebra Forum
    Replies: 4
    Last Post: May 22nd 2012, 05:43 AM
  2. Algeb
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 18th 2012, 05:59 AM
  3. Algeb
    Posted in the Algebra Forum
    Replies: 4
    Last Post: May 17th 2012, 05:24 AM
  4. Algeb
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 16th 2012, 06:12 AM
  5. Algeb
    Posted in the Algebra Forum
    Replies: 5
    Last Post: May 15th 2012, 07:01 AM

Search Tags


/mathhelpforum @mathhelpforum