1. ## Algeb

if the quadratic equation $2x^2-qx+r=0$have the roots $(\alpha+1),(\beta+2)$find out the value of q,r in terms of b,c. $x^2-bx+c=0$the quadratic equation have the real roots $\alpha,\beta$ and also $\ \alpha\geq\beta$if $\ \alpha=\beta$prove $q^2=4(2r+1)$

2. ## Re: Algeb

Originally Posted by srirahulan
if the quadratic equation $2x^2-qx+r=0$have the roots $(\alpha+1),(\beta+2)$find out the value of q,r in terms of b,c. $x^2-bx+c=0$the quadratic equation have the real roots $\alpha,\beta$ and also $\ \alpha\geq\beta$if $\ \alpha=\beta$prove $q^2=4(2r+1)$
Using the product of the roots we get $(\alpha +1)(\beta +2)=\frac{r}{2}$ and $(\alpha)(\beta)=c$

Using the sum of the roots we get $\alpha +\beta+3 =\frac{q}{2}$ and $\alpha +\beta=b$