To "see" how this works, start with a right triangle: 10 by 24 by 26 will make it easier...
I found this question and I could do with some help regarding the answer. It is:
Nine lines are drawn parallel to the base of a triangle to divide each of the other sides into 10 equal segments. If the area of the largest region is 38, find the area of the original triangle.
I believe that it must be ratios and something like:
(Sorry bad drawing!)
Ratio of sides =
Therefore, ratio of areas =
Therefore area =
Am I right? I feel that this is rather inadequate and too simple.
Thanks very much for any help!
Alternatively you could use the standard formula for the area of a triangle with sides and included angle
Call the sloping sides and say, then the area of the last strip will be
in which case so that the area of the whole triangle will be
A model triangle has an altitude of 10 units and a base of10 units. Its area = 50 sq units
Area of largest trapezoid section = 50 - 9*9/2 =9.5 sq units
Fractional area of above 9.5/50 = 0.19
Area of actual triangle* 0.19 =38
AAT = 200 sq units
Here's another approach . . .
Nine lines are drawn parallel to the base of a triangle to divide each of the other sides into 10 equal segments.
If the area of the largest region is 38, find the area of the original triangle.
The base of the triangle is ; its height isCode:- * : * * : * * : * * h * * : * (9/10)b * : * * * * * * * * * * - - - : * * (1/10)h - * * * * * * * * * - : - - - - - b - - - - - :
The bottom trapezoid has height and bases and
Its area is 38: .
j = area largest region (38)
h = height of triangle (10)
n = number of regions (10)
k = area of triangle (?)
k = bh / 2
where b = 2jn(n - 2) / [2(h/n)(n^2 - 3n + 1) + h]
(b = base of triangle)
Substitute the givens and you'll get b = 40, hence k = 40(10) / 2 = 200
Now Bob, you can use that as a "general case" formula;
weird ones like j = 137, h = 23, n = 7 handled quickly!
That one will give you b = 44.903.... and k = 516.384....