Hi,

I found this question and I could do with some help regarding the answer. It is:

Nine lines are drawn parallel to the base of a triangle to divide each of the other sides into 10 equal segments. If the area of the largest region is 38, find the area of the original triangle.

I believe that it must be ratios and something like:

(Sorry bad drawing!)

Ratio of sides = $\displaystyle 10x:9x$

Therefore, ratio of areas = $\displaystyle 100x^2 : 81x^2$

$\displaystyle 100x^2-81x^2=38$

$\displaystyle 19x^2=38$

$\displaystyle x^2=2$

Therefore area = $\displaystyle 100x^2=200$

Am I right? I feel that this is rather inadequate and too simple.

Thanks very much for any help!