# How do you rearrange this equation?

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• May 26th 2012, 03:14 AM
Zack171195
How do you rearrange this equation?
Sorry if it seems basic but I do not know how I would go about rearranging the bellow equation for t. Any help would be much appreciated.
x=t-2sin(t)

Thanks,
Z.C.
• May 26th 2012, 03:20 AM
Siron
Re: How do you rearrange this equation?
You'll need a numerical method to solve this equation for $\displaystyle t$
• May 26th 2012, 07:06 PM
Zack171195
Re: How do you rearrange this equation?
Thanks for the reply,

I'm not 100% sure what a numerical method is... Could you please give an example?

Thanks again,
Z.C.
• May 26th 2012, 07:43 PM
Wilmer
Re: How do you rearrange this equation?
Quote:

Originally Posted by Zack171195
I'm not 100% sure what a numerical method is... Could you please give an example?

Google "solving using numerical methods"
• May 26th 2012, 08:25 PM
Prove It
Re: How do you rearrange this equation?
Quote:

Originally Posted by Siron
You'll need a numerical method to solve this equation for $\displaystyle t$

Wouldn't you need \displaystyle \displaystyle \begin{align*} x \end{align*} to be set equal to a NUMBER in order to use a numerical method?
• May 27th 2012, 03:29 AM
Siron
Re: How do you rearrange this equation?
Quote:

Originally Posted by Prove It
Wouldn't you need \displaystyle \displaystyle \begin{align*} x \end{align*} to be set equal to a NUMBER in order to use a numerical method?

You're right, the solution space will be one-dimensional.
• Jun 1st 2012, 02:12 PM
Zack171195
Re: How do you rearrange this equation?
Hello Again,
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I've been doing some stuff on this problem using excel. What I did was get values for t and solve for x then graph so as x was the x-axis and t the y-axis. This produced a function as shown in the first below graph (labelled original). The equation of this curve is the answer to my question however I do not know how to determine what its equation is. As seen using a linear approximation the gradient of the line is essentially: t=x. The actual equation is therefore actually modeled by: y=mx+c+k; where c=0, m=1, x=x and y=t: t=x+k. Therefore I figured in order to determine the actual equation of the curve I needed to find K. [k=t-x] Graphing this (K=y-axis and x=x-axis) gave the "New" function. I figured that K would be a simple sine function which I know how to regress the equation of visually, however as seen the function ("new" in the below image), is a skewed function. I have had no experience at all in determining the equation of a skewed sine function. So my question is:
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Could someone please tell me how I would go about determining the equation of the "New" function in the below graph?
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Attachment 24010
[First Graph]
Attachment 24009
[Graph of "New" from first graph]

Any help would be greatly appreciated.
Thanks,
Z.C.