I did a few more of these types of problems...could someone please take a look at them...I would like to make sure that I am doing the correctly...

http://i103.photobucket.com/albums/m...919/111002.jpg

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- Oct 3rd 2007, 03:39 PMaikenfanRational expressions
I did a few more of these types of problems...could someone please take a look at them...I would like to make sure that I am doing the correctly...

http://i103.photobucket.com/albums/m...919/111002.jpg - Oct 3rd 2007, 04:25 PMtopsquark
You really need to work on using parenthesis. For example in 7 you have [tex]2x + 1(x + 1)[tex] instead of $\displaystyle (2x + 1)(x + 1)$. You have a similar error in 8 and 14. (This, in fact, caused your answers to 8 and 14 to be incorrect.)

In 11, $\displaystyle -3(x - 1)$ is equal to what?

The rest looks good.

-Dan - Oct 3rd 2007, 04:45 PMaikenfan
For number 8, I now get: (2x^2 + 4)/ (x-2)(x+2)

For number 14, I get (-7x^2 + 65x + 372)/(x + 4)(x - 3) - Oct 3rd 2007, 04:56 PMtopsquark
- Oct 3rd 2007, 05:05 PMaikenfan
The numerator for 8 is 2x^2 + 8

- Oct 3rd 2007, 05:07 PMaikenfan
93 and -28 multiply to get -2604 and add to get 65...im a little confused...what do I do with that now?

it would be (x + 93)(x - 28)? - Oct 3rd 2007, 05:10 PMtopsquark