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Math Help - simplifying help

  1. #1
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    simplifying help

    Can someone please explain, how  \frac{k^{2}(k+1)^{2} +4(k+1)^{3}}{4} simplifies to

     \frac{({k+1}^{2})k^{2}+4(k+1)}}{{4}}
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  2. #2
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    Re: simplifying help

    Quote Originally Posted by Tweety View Post
    Can someone please explain, how  \frac{k^{2}(k+1)^{2} +4(k+1)^{3}}{4} simplifies to

     \frac{({k+1}^{2})k^{2}+4(k+1)}}{{4}}
    Well it does not!

     \frac{k^{2}(k+1)^{2} +4(k+1)^{3}}{4}=\frac{(k+1)^{2}[k^{2} +4(k+1)]}{4}=\frac{(k+1)^{2}[(k+2)^2]}{4}
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  3. #3
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    Re: simplifying help

    Quote Originally Posted by Plato View Post
    Well it does not!

     \frac{k^{2}(k+1)^{2} +4(k+1)^{3}}{4}=\frac{(k+1)^{2}[k^{2} +4(k+1)]}{4}=\frac{(k+1)^{2}[(k+2)^2]}{4}
    but your second expression is exactly the same as my second expression. I know it simplifies to your last expression, but I dont understand the second part.
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  4. #4
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    Re: simplifying help

    Quote Originally Posted by Tweety View Post
    but your second expression is exactly the same as my second expression. I know it simplifies to your last expression, but I dont understand the second part.
    No it is not.
    Look at the grouping symbol [~~]
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  5. #5
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    Re: simplifying help

    I think I got it, we factor out a (k+1) term, from  (k+1)^{2} and from  (k+1)^{3}
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  6. #6
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    Re: simplifying help

    Make your life easier: remove the division by 4; let x = k+1
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