a) given that 2^x = 1/[rt2] and 2^y = 4[rt2]

find the exact value of x and the exact value of x

b) given that 4^x = 8^(2-x) find the value of x

c) given that3^x = 9^(y-1) show that x = 2y-2

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- Oct 3rd 2007, 09:32 AMkls7162algebra need for 2moz
a) given that 2^x = 1/[rt2] and 2^y = 4[rt2]

find the exact value of x and the exact value of x

b) given that 4^x = 8^(2-x) find the value of x

c) given that3^x = 9^(y-1) show that x = 2y-2 - Oct 3rd 2007, 09:39 AMJhevon
I'll start you off

$\displaystyle 2^x = \frac 1{\sqrt{2}}$

take log to the base 2 of both sides:

$\displaystyle \Rightarrow \log_2 2^x = \log_2 \left( \frac 1{\sqrt{2}}\right)$

$\displaystyle \Rightarrow x \log_2 2 = \log_2 \left( \frac 1{\sqrt{2}}\right)$

$\displaystyle 2^y = 4 \sqrt {2}$

do the same thing here:

Quote:

b) given that 4^x = 8^(2-x) find the value of x

$\displaystyle 4 = 2^2$ and $\displaystyle 8 = 2^3$

So we have $\displaystyle \left( 2^2 \right)^x = \left( 2^3 \right)^{2 - x}$

now continue

Quote:

c) given that3^x = 9^(y-1) show that x = 2y-2

now continue