Im new and i hope you guys can help me with this showing me solution and steps by steps. as im a newbie .. Thanks! log4x-log4(2x-7)= -2
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Originally Posted by Sleepy92 Im new and i hope you guys can help me with this showing me solution and steps by steps. as im a newbie .. Thanks! log4x-log4(2x-7)= -2 Is the question $\displaystyle \log_4(x)-\log_4(2x-7)= -2~?$
Yes thanks for doing it for me .. i dont know how to do it like you
Originally Posted by Sleepy92 Yes thanks for doing it for me .. i dont know how to do it like you Use LaTeX coding [TEX]\log_4(x)-\log_4(2x-7)= -2~?[/TEX] gives $\displaystyle \log_4(x)-\log_4(2x-7)= -2~?$. Note $\displaystyle \log_4(x)-\log_4(2x-7)=\log_4\left(\frac{x}{2x-7}\right)$ Recall $\displaystyle \log_b(a)=c$ means $\displaystyle a=b^c~.$