If quadratic equations have a common root.prove b=c or the other roots are the roots of
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Originally Posted by srirahulan If quadratic equations have a common root.prove b=c or the other roots are the roots of The roots of the first equation are and the roots of the second equation are Since they share a root, there is some value such that If , we have So that means for the two equations to share a root, it's possible that .
I can't understand you statements.pls reply,
Originally Posted by srirahulan ....are the roots of k = [abc - (b+c)] / [a(b+c)] x = +- SQRT(k)
Originally Posted by srirahulan If quadratic equations have a common root.prove b=c or the other roots are the roots of x^2 + abx + c = 0 [1] x^2 + acx + b = 0 [2] Roots of [1] = u,v Roots of [2] = u,w Then: ab = u + v c = uv : v = c/u ab = u + c/u : a = (u + c/u) / b [3] Similarly: a = (u + b/u) / c [4] [3][4]: (u + c/u) / b = (u + b/u) / c Simplify: bu^2 + b^2 = cu^2 + c^2 b = c
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