three numbers of a geometric progression whose sum is 28 and whose product is 512. find the first three numbers

the problem above, i have attempted it and arrived at 8,16,32

am i correct? thanks

Printable View

- May 21st 2012, 04:06 AMlawochekeldefinite series!
three numbers of a geometric progression whose sum is 28 and whose product is 512. find the first three numbers

the problem above, i have attempted it and arrived at 8,16,32

am i correct? thanks - May 21st 2012, 04:27 AMPlatoRe: definite series!
- May 21st 2012, 04:53 AMProve ItRe: definite series!
- May 21st 2012, 01:55 PMbjhopperRe: definite series!
Try this

3 terms a,ar.ar^2 Product = 512 = a^3 r^3 a = 8/r second term =8 third term = 8r

add the 3 terms whose sum =28 . This will produce a quadratic equation giving the r value