I have the following
12.0*1.08^x =25.0
I need to find the value of x but Im lost on how its done.
Dave
1. Divide through by 12.0.
2. Actually you have an exponential term at the LHS so transform the RHS into an exponential term with the same base:
$\displaystyle \displaystyle{1.08^x = 1.08^{\log_{1.08}\left(\frac{25}{12} \right)}}$ ............ So $\displaystyle x = \log_{1.08}\left(\frac{25}{12} \right)$
3. To get an approximate value for x use the base change formula:
$\displaystyle \log_a(b)=\frac{\ln(b)}{\ln(a)}$
Use your calculator.