I have the following
12.0*1.08^x =25.0
I need to find the value of x but Im lost on how its done.
Dave
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I have the following
12.0*1.08^x =25.0
I need to find the value of x but Im lost on how its done.
Dave
1. Divide through by 12.0.Quote:
Originally Posted by davellew69
2. Actually you have an exponential term at the LHS so transform the RHS into an exponential term with the same base:
............ So
3. To get an approximate value for x use the base change formula:
Use your calculator.
can this be done by using algebra?
That is algebra.
I would simply use log base 10. No need to change.
log 12 + x(log 1.08) = log 25
x= 9.5
1.08^x = 25/12
x = log(25/12) / log(1.08)
If a^x = b then x = log(b) / log(a) : tattoo that on your wrist!