8/(9x-9) + 9(9-9x)
Could someone walk me through how to get the answer to this question?
I get as far as
8/(9x-9) + 1/(1-x)
I know the answer is 1/(9-9x) but I dont know how to get there from the above?
Thanks.
I assume the fraction is missing in that last term, but you mean:
$\displaystyle \frac{8}{9x-9}+\frac{9}{9-9x}$
Notice that the denominators are almost equal, but you can (for example) make them equal by rewriting the second term:
$\displaystyle \frac{9}{9-9x} = \frac{9}{-(-9+9x)} = -\frac{9}{9x-9}$
Now you can also easily add (substract) both fractions.