Algeb

**srirahulan** · May 16th 2012, 10:15 PM

$\mbox{if}\ a^2x^2+6abx+ac+8b^2=0\ \mbox{have equal roots then,prove}\ ac(x+1)^2 =4b^2x\ \mbox{have equal roots.}$

**Goku** · May 16th 2012, 11:08 PM

use the quadratic formula for the first one and solve:

$\frac{-6ab \pm \sqrt{36a^2b^2 - 4a^2(ac+8b^2)}}{2a^2}$

find the 2 solution and equate......

**srirahulan** · May 17th 2012, 04:48 AM

I can't understand.

**Goku** · May 17th 2012, 05:00 AM

Suppose that $a^2x^2+6abx+ac+8b^2$ has equal roots,

what will this mean....

First Solve the equation using the quadratic equation and tell me what you get....

**Wilmer** · May 17th 2012, 05:24 AM

$\frac{-6ab \pm \sqrt{36a^2b^2 - 4a^2(ac+8b^2)}}{2a^2}$

For roots to be equal, discriminant = 0, right? So:
36 a^2 b^2 = 4 a^2(ac + 8 b^2); simplifies to b^2 = ac

Now continue with other equation...

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