# Sound intensity

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• May 16th 2012, 06:16 PM
lamp23
Sound intensity
$B=log(\frac{I}{I_{0}})$

If B=58.4 dB and $I_{0}=10^{-12} \frac{W}{m^2}$

then:

$58.4=log(\frac{I}{10^{-12}})$

log(I/
• May 16th 2012, 06:57 PM
Moebius
Re: Sound intensity
If you are wanting to know $I$ it is as follows:

$58.5=log(\frac{I}{10^{-12}})$

$10^{58.5}=\frac{I}{10^{-12}}$

$(10^{58.5})(10^{-12})=I$

$I=3.16 \times 10^{46}$
• May 20th 2012, 05:24 PM
lamp23
Re: Sound intensity
I meant to delete this. Can I not delete it after a set amount of time?