Hi. I feel a complete simpleton. How do I get this: (2 - x)^{2}(3 - x) - (3 - x) to be this: (1 - x)(3 - x)^{2 } I am utterly stuck with this. Thanks for any help!
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$\displaystyle (2 - x)^2(3 - x) - (3 - x) $ take $\displaystyle (3-x)$ common and try solving, by expanding $\displaystyle (2-x)^2$
thanx amul28. i don't know what i was doing wrong... (3 - x)[(2 - x)(2 - x) - 1] = (3 - x)(3 - 4x + x^2) = (3 - x)(3 - x)(1 - x) cheers
$\displaystyle (2-x)^2(3-x)-(3-x)=(3-x)((2-x)^2-1)=(3-x)(2-x-1)(2-x+1)=$ $\displaystyle =(1-x)(3-x)^2$
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