I have $\displaystyle \frac{(n+1)^n}{n^n}$

this somehow equals:

$\displaystyle (1+\frac{1}{n})^n$

Can someone show me the step in between? I just can't seem to make it work...

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- May 9th 2012, 06:51 PMBowlbasesimple division?
I have $\displaystyle \frac{(n+1)^n}{n^n}$

this somehow equals:

$\displaystyle (1+\frac{1}{n})^n$

Can someone show me the step in between? I just can't seem to make it work... - May 9th 2012, 07:08 PMamul28Re: simple division?
$\displaystyle \frac {(n+1)^n} {n^n}$

$\displaystyle \implies \big (\frac {n+1} {n} \big )^n$ [which is the same]

$\displaystyle \implies (1+\frac {1} {n})^n$ [separating the denominator for n and 1]

Thanks - May 9th 2012, 07:20 PMBowlbaseRe: simple division?
thanks, I knew I was just missing something simple as always.

I appreciate the help.