For 3rd number it is clearer to write (3n+2-n)/2=(2n+2)/2=n+1
"The sum of three numbers is 38. The second number is 2 more than three times the first number. The third number is equals half the difference between the first two numbers. What are the numbers?"
Here's what I have so far:
n = the first number
3n+2 = the second number
3n+2-n/2 = the third number
Am I correct so far?
So I should have the following:
n+3n+2+(3n+2-n)/2=38
2n+6n+4+3n+2-n=76
10n+6=76
10n=70
n=7
n=7 (first number)
3(7)+2=23 (second number)
23-7=16/2
=8 (third number)
7, 23, 8
Hope that's right!
"The sum of three numbers is 38. The second number is 2 more than three times the first number. The third number is equals half the difference between the first two numbers. What are the numbers?"
As you say, calling the first number n, the second number is 3n+ 2 and the third number is ((3n+2)- n)/2= (2n+ 2)/2= 2(n+1)/2= n+ 1.
But that does NOT tell you what the individual numbers are. If the first number is 1, then the second number is 5 and the third number is 3. If the second number is 2, the second number is 8 and the third number is 3. You can take any number to be the first number and then find values for the second number and third number.