1. log 3 + log (5x - 2) = log (9x + 6) 2. 2 log (2x - 1) = 2 log (3x + 1) - log 4 3. log_2 (x - 4) + log_2 (x - 3) = 1 Please Help!
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Originally Posted by jwhite09 1. log 3 + log (5x - 2) = log (9x + 6) Look at the left hand side: log 3 + log (5x - 2) = log(3(5x-2)) = log(15x-6), so: 15x-6 = 9x+6. Now try the same sort of thing on the remainder. RonL
Originally Posted by jwhite09 1. log 3 + log (5x - 2) = log (9x + 6) Originally Posted by jwhite09 2. 2 log (2x - 1) = 2 log (3x + 1) - log 4 You can solve for x here, I'm lazy. Originally Posted by jwhite09 3. log_2 (x - 4) + log_2 (x - 3) = 1
Last edited by janvdl; Oct 2nd 2007 at 11:10 AM. Reason: Typo
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