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Math Help - Solving for z

  1. #1
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    Solving for z

    g=h(x+y/z-x) solve for z

    The solution I keep getting is...

    z= hx+hy-gx/-g

    should this be the correct answer?
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  2. #2
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    Re: Solving for z

    If you mean :

    g=h\cdot\left(\frac{x+y}{z-x}\right)

    then solution should be :

    z=x+\frac{h(x+y)}{g}
    Last edited by princeps; May 8th 2012 at 07:52 AM.
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  3. #3
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    Re: Solving for z

    The book show something totally different
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  4. #4
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    Re: Solving for z

    Quote Originally Posted by Builderjay2011 View Post
    The book show something totally different
    1. What does the book show?

    2. What have you tried?
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  5. #5
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    Re: Solving for z

    How do you all show the formating of your formulas? Makes it easier for me to show my work to you.
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  6. #6
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    Re: Solving for z

    It's called LaTeX. There is a LaTeX subforum on this site where you can get some help on the coding.
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  7. #7
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    Re: Solving for z

    Ok here's what I did....

    g=h(x+y/x-z) for z

    multiply both sides by (x-z)

    g(x-z) = h(x+y)

    gx-gz-gx = hx+hy-gx (clear parentheses and subtract "gx" from both sides)

    -gz = hx+hy-gx

    z = hx+hy-gx/-g

    Let me know if this makes sense.
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  8. #8
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    Re: Solving for z

    Quote Originally Posted by Builderjay2011 View Post
    Ok here's what I did....

    g=h(x+y/x-z) for z

    multiply both sides by (x-z)

    g(x-z) = h(x+y)

    gx-gz-gx = hx+hy-gx (clear parentheses and subtract "gx" from both sides)

    -gz = hx+hy-gx

    z = (hx+hy-gx)/-g

    Let me know if this makes sense.
    With the necessary modification, what you have is fine.
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