Thread: Simplify equation with steps

(64n^9)^²/₃

(5b^2c^¹/₄)^3

Originally Posted by jobbles85

(64n^9)^²/₃

(5b^2c^¹/₄)^3

Not showing steps, that's your job.

You need to use the following index laws:

Originally Posted by Prove It

Not showing steps, that's your job.

You need to use the following index laws:

so would the steps be..
=64n9x2/3
=64n^6

Originally Posted by jobbles85

so would the steps be..
=64n9x2/3
=64n^6

correction ...



finish by simplifying the factor ...

(64n^9)^2/3
=642/3n^6
=(3√64^2)(n^6)
=(3√4096)(n^6)
=±16n^6

God I have no clue what I'm doing

(5b^2c^1/4)^3
=(5)^3 (b^2)^3 (c^1/4)^3
=125b^5c^3/4

would have been really easy if you knew that ... and it's not

last one is correct