# Simplify equation with steps

• May 6th 2012, 04:57 PM
jobbles85
Simplify equation with steps
(64n^9)^2/3

(5b^2c^1/4)^3
• May 6th 2012, 07:15 PM
Prove It
Re: Simplify equation with steps
Quote:

Originally Posted by jobbles85
(64n^9)^2/3

(5b^2c^1/4)^3

Not showing steps, that's your job.

You need to use the following index laws:

\displaystyle \displaystyle \begin{align*} \left(a^m\right)^p &= a^{m \cdot p} \\ \\ \left(a \cdot b\right)^n &= a^n \cdot b^n \end{align*}
• May 7th 2012, 10:10 AM
jobbles85
Re: Simplify equation with steps
Quote:

Originally Posted by Prove It
Not showing steps, that's your job.

You need to use the following index laws:

\displaystyle \displaystyle \begin{align*} \left(a^m\right)^p &= a^{m \cdot p} \\ \\ \left(a \cdot b\right)^n &= a^n \cdot b^n \end{align*}

so would the steps be..
=64n9x2/3
=64n^6
• May 7th 2012, 10:21 AM
skeeter
Re: Simplify equation with steps
Quote:

Originally Posted by jobbles85
so would the steps be..
=64n9x2/3
=64n^6

correction ...

$\displaystyle (64n^9)^{\frac{2}{3}} = 64^{\frac{2}{3}}n^6$

finish by simplifying the factor $\displaystyle 64^{\frac{2}{3}}$ ...
• May 7th 2012, 12:39 PM
jobbles85
Re: Simplify equation with steps
(64n^9)^2/3
=642/3n^6
=(3√64^2)(n^6)
=(3√4096)(n^6)
=±16n^6

God I have no clue what I'm doing

(5b^2c^1/4)^3
=(5)^3 (b^2)^3 (c^1/4)^3
=125b^5c^3/4
• May 7th 2012, 12:44 PM
skeeter
Re: Simplify equation with steps
would have been really easy if you knew that $\displaystyle 64 = 4^3$ ... and it's not $\displaystyle \pm$

last one is correct