Hi sorry to ask, I am doing logs,but Im lost onsqroot 2 = 2^0.5

Dave

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- May 4th 2012, 12:54 PMdavellew69sqroot 2 = 2^0.5
Hi sorry to ask, I am doing logs,but Im lost on

**sqroot 2 = 2^0.5**

Dave - May 4th 2012, 01:10 PMMathoManRe: sqroot 2 = 2^0.5
Generally $\displaystyle \sqrt[n]{a}=a^{\frac{1}{n}}$. So $\displaystyle \sqrt{2}=\sqrt[2]{2}=2^{\frac{1}{2}}=2^{0.5}.$

- May 4th 2012, 01:15 PMdavellew69Re: sqroot 2 = 2^0.5
thanks, I forgot indice laws

- May 4th 2012, 06:14 PMHallsofIvyRe: sqroot 2 = 2^0.5
Grammatical point- there is no such word as "indice". "Indices" is the plural of "index".