(c^2-2c-4)/(c+4) = c-6+20/c+4 But it's reducible remainder, therefor I believe it is wrong.....
Last edited by Kanderson; May 3rd 2012 at 01:59 PM.
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You have the right answer. $\displaystyle \frac{c^2-2c-4}{c+4}=c-6+\frac{20}{c+4}$
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