(c^2-2c-4)/(c+4) = c-6+20/c+4 But it's reducible remainder, therefor I believe it is wrong.....

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- May 3rd 2012, 01:41 PMKandersonPolynomial division
(c^2-2c-4)/(c+4) = c-6+20/c+4 But it's reducible remainder, therefor I believe it is wrong.....

- May 3rd 2012, 02:24 PMa tutorRe: Polynomial division
You have the right answer.

$\displaystyle \frac{c^2-2c-4}{c+4}=c-6+\frac{20}{c+4}$