Hi guys, I need some help with a question from the IB HL maths papers.

Not sure how this works:

Sin(2n+1)xcosx - cos(2n+1)xsinx = sin(2n+1)x - x = sin 2nx

Could some1 show me more detailed steps or give me some hints on how equation holds?

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- May 2nd 2012, 06:45 AMholabooQuestion with Trigonometric functions
Hi guys, I need some help with a question from the IB HL maths papers.

Not sure how this works:

Sin(2n+1)xcosx - cos(2n+1)xsinx = sin(2n+1)x - x = sin 2nx

Could some1 show me more detailed steps or give me some hints on how equation holds? - May 2nd 2012, 06:48 AMProve ItRe: Question with Trigonometric functions
- May 2nd 2012, 06:50 AMholabooRe: Question with Trigonometric functions
oh sorry, all the x are X, not times I'm not sure how to insert mathematic symbols...

- May 2nd 2012, 06:50 AMholabooRe: Question with Trigonometric functions
Sin(2n+1)x . cosx - cos(2n+1)x . sinx = sin(2n+1)x - x = sin 2nx

- May 2nd 2012, 06:55 AMProve ItRe: Question with Trigonometric functions
Apply with and .

- May 2nd 2012, 06:59 AMholabooRe: Question with Trigonometric functions
thanks I just worked it out myself too. Is the Sin A-B formula derived from the Sin A+B formula? Could you do the same for the Cos A+B formula?

- May 2nd 2012, 07:14 AMProve ItRe: Question with Trigonometric functions