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Thread: proof

  1. April 30th 2012, 08:02 AM #1
    Mhmh96
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    proof

    How to prove that:

    1994^2000+1995^2000<1996^2000
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  2. April 30th 2012, 08:24 AM #2
    emakarov
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    Re: proof

    1996^{2000}=(1995+1)^{2000}=1995^{2000}+2000\cdot1 995^{1999}+\dots. Now, 2000\cdot1995^{1999}>1994\cdot1994^{1999}=1994^{20 00}.
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