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Math Help - proof

  1. #1
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    proof

    How to prove that:

    1994^2000+1995^2000<1996^2000
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  2. #2
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    Re: proof

    1996^{2000}=(1995+1)^{2000}=1995^{2000}+2000\cdot1  995^{1999}+\dots. Now, 2000\cdot1995^{1999}>1994\cdot1994^{1999}=1994^{20  00}.
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