whats solution to (3)^2x-36(3)^x+243=0
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$\displaystyle (3^x)^2-36(3^x)+243=0$ Substitute $\displaystyle y=3^x$ if you like. Factorise.
then you just use quadratic formula?
That will certainly work.
your solution set is 9, -27, but when i try testing them with original equation im not getting right answer, is there something im missing
Originally Posted by kukid13 your solution set is 9, -27, but when i try testing them with original equation im not getting right answer, is there something im missing you should have found 9 and +27 for your quadratic solutions ..
but when i try to plug those back into equation im coming up with funky answers? what am i missing
Originally Posted by kukid13 but when i try to plug those back into equation im coming up with funky answers? what am i missing $\displaystyle 3^x = 9$ $\displaystyle x = 2$ you do the other solution ...
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