Thread: Inequalities / Interval notation

Find all values of x satisfying the inequalities. Present your answer using the interval notation and illustrate it with the help of the number axis.

Hey guys.
I just wanted to know if I'm on the right track with these questions.

a) (x - 1) (2x + 3) > 0

answer: x > 1 , x > - 1.5


b) |7 + 2x| >/_ 3


answer: x>/_ 3 (x is greater than or equal to 3)


c) |2x - 7| </_ 3x - 10


answer: x >/_ -2 or x >/_ -5 (x is greater than or equal to -2 or x is greater than or equal to -5)



(Apologies for the greater than / equal to signs - I didn't know how to in put them. The underscore (_) represents the equal to sign)

I'm just not sure about the interval notation and how you represent it on the number axis.

type \leq for :

and

type \geq for :

link

Two comments about part a. If x>1 it will be greater than -3/2 so that part of the answer is just x>1

Now use the fact that if both brackets are negative (that is <0) the product will be >0

So its not x>-1.5 just x>1 ?

Yes. Any value that is greater than 1 will also be greater than -1.5 so we don't need to write x greater than -1.5 as well as x greater than 1

a) seems to be resolved

b) for this one please remember the rule or

following the rule



or

or

or are your solutions

c) similar situation but remember the rule