Thread: Re-arrange equation for D

I am trying to rearrange this equation

Q=0.098[(D^4-d^4)/D]

For D=

I have spent to hours factoriseing, swapping sides, etc. but im getting nowhere.

Please Help

WA

What does "WA" mean

Originally Posted by gwood311

I am trying to rearrange this equation

Q=0.098[(D^4-d^4)/D]

For D=

I have spent to hours factoriseing, swapping sides, etc. but im getting nowhere.

Please Help

So "D" and "d" are different? "D" is the value you want to determine and "d" is some given value?



Multiply both sides by D:


Do the multiplication on the right and subtract QD from both sides:

Now that is a fourth degree equation. There is a "formula" for solving general fourth degree equations but it is very complicated:
Quartic function - Wikipedia, the free encyclopedia

Originally Posted by gwood311

What does "WA" mean

princeps provided a link to Wolfram Alpha , an online computational site ... click on his WA

Hi friends, Algebra is really very complicated, even i was facing such problem in Algebra. You guys are really working hard and helping each by solving each other Algebra queries. You can also go for online Algebra Tutor.

Thanks for help guys. Didn't realise the WA was a hyperlink, thanks.

After looking into the 4th degree equation I found the equation must be in the format:

ax^4 + bx^2 + c=0

In my equation the middle part is not squared so I cannot solve the equation.

I am beginning the think the equation cannot be rearranged simply for D and the only answer for it is on WA provided by princeps

Originally Posted by gwood311

Thanks for help guys. Didn't realise the WA was a hyperlink, thanks.
After looking into the 4th degree equation I found the equation must be in the format:
ax^4 + bx^2 + c=0
In my equation the middle part is not squared so I cannot solve the equation.

That equation is a quadratic; let u = x^2, then au^2 + bu + c = 0.

That equation is a quadratic; let u = x^2, then au^2 + bu + c = 0.

My equation which is; 0.098D^4 - QD - 0.098d^4 = 0

Letting u=D^2 in this case will not work.

Originally Posted by gwood311

That equation is a quadratic; let u = x^2, then au^2 + bu + c = 0.

My equation which is; 0.098D^4 - QD - 0.098d^4 = 0

Letting u=D^2 in this case will not work.

Right. I was referring to : ax^4 + bx^2 + c = 0

0.098D^4 - QD - 0.098d^4 = 0

That one is really: 0.098D^4 + 0D^3 + 0D^2 - QD - 0.098d^4 = 0
or : 98D^4 + 0D^3 + 0D^2 - 1000QD - 98d^4 = 0