I am trying to rearrange this equation
Q=0.098[(D^4-d^4)/D]
For D=
I have spent to hours factoriseing, swapping sides, etc. but im getting nowhere.
Please Help
So "D" and "d" are different? "D" is the value you want to determine and "d" is some given value?
$\displaystyle Q= 0.098\frac{D^4- d^4}{D}$
Multiply both sides by D:
$\displaystyle QD= 0.098(D^4- d^4)$
Do the multiplication on the right and subtract QD from both sides:
$\displaystyle 0.098D^4- QD- d^4= 0$
Now that is a fourth degree equation. There is a "formula" for solving general fourth degree equations but it is very complicated:
Quartic function - Wikipedia, the free encyclopedia
Thanks for help guys. Didn't realise the WA was a hyperlink, thanks.
After looking into the 4th degree equation I found the equation must be in the format:
ax^4 + bx^2 + c=0
In my equation the middle part is not squared so I cannot solve the equation.
I am beginning the think the equation cannot be rearranged simply for D and the only answer for it is on WA provided by princeps