Factor completly: (3n-1)^{2 }- (3n-1) - 72 What do you use to process this? If there is nothing to work with the -72? You can factor out (3n-1) correct? But still left with the -72?
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Originally Posted by Kibbygirl Factor completly: (3n-1)^{2 }- (3n-1) - 72 $\displaystyle x^2-x-72=(x-9)(x+8)$. Let $\displaystyle x=3n-1.$
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