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My problem states to factor completely:
49c+56c+16
Nothing can be factored out as it is. So I took the product of 49 & 16 = 784 and two integers whose products equal 784 and sum equals 56 is (28)(28)
Yet when I go to factor, it's not adding up. Maybe I am confusing the steps?
49c2+28c+28c+16
28c(c+21c) ?
I am not sure what I am suppose to do actually...
Hello, Kibbygirl!
Quote:
Factor completely: .
Nothing can be factored out as it is.
So I took the product of 49 & 16 = 784
. . and two integers whose products equal 784 and sum equals 56 is (28)(28).
Yet when I go to factor, it's not adding up. Maybe I am confusing the steps?
. This is correct!
28c(c+21c) ? .But what is this?
You are supposed to "factor by grouping".
Are you familiar with it?
You have: .
Factor the terms "by pairs".
. . You can factorfrom the first two terms
. . You can factorfrom the last two terms.
Then you have: .
Note that the term groups haveon common . . . factor it out!
And we have: .
See how it works?
Thank you! I didn't realize I should be factor by grouping, I was trying to do the form x2+bx+c. I am vaguely familiar with factoring by grouping, so thank you for the steps.
Soroban, can you tell me why in your final it is - and not +? Everything I am seeing in my book shows it'd be (7c+4)2??
That was just a typo.Quote:
Originally Posted by Kibbygirl
Ok great, just wanted to verify in case I am not understanding correctly. :)
