• April 24th 2012, 12:04 PM
Capnzims
The question is this and i get the answer x = 125 which when i plug it back in I think it works.

1+ root 5 radical x = 9 -7 root 5 radical x

the book says the answer is 125/4 i dont agree can anyone confirm
• April 24th 2012, 12:08 PM
Capnzims
actually wrong problem
real problem

3 root 3 radical x = 5 +2 root 3 radical x
• April 24th 2012, 12:10 PM
Plato
Quote:

Originally Posted by Capnzims
The question is this and i get the answer x = 125 which when i plug it back in I think it works.
1+ root 5 radical x = 9 -7 root 5 radical x
the book says the answer is 125/4 i dont agree can anyone confirm

Is this the question: $1+\sqrt{5}\sqrt{x}=9-7\sqrt{5}\sqrt{x}~?$
If not, try to make it clearer.
• April 24th 2012, 12:25 PM
Capnzims
Sure my apology

its the 3 the cube of x = 5 + 2 the cube of x
Like the 3 is beside the radical with a little 3 outside of the radical and x is inside the radical
and the 2 is beside the radical with a ilttle 3 outside of the radical and x is inside the radical
• April 24th 2012, 12:46 PM
Plato
Quote:

Originally Posted by Capnzims
Sure my apology

its the 3 the cube of x = 5 + 2 the cube of x
Like the 3 is beside the radical with a little 3 outside of the radical and x is inside the radical
and the 2 is beside the radical with a ilttle 3 outside of the radical and x is inside the radical

\begin{align*}\sqrt[3]{x}&=5+2\sqrt[3]{x}\\\sqrt[3]{x}&=-5\\x&=-125\end{align*}
• April 24th 2012, 12:48 PM
Capnzims
Thats the equation but there is a 3 beside the first radical so 3 little 3 radical x
I got the answer 125. Am i right?
• April 24th 2012, 12:54 PM
Plato