how do i solve for z? can someone help to show me step by step in how to solve for z?
100 = ( (7/ (1 + z)^1) + (107/ (1 + z)^2) )
Let A and B be the 2 terms on the right hand side
So 100 = A+B Multiplying each term by (i+z)^2 we get 100(1+z)^2= A(1+z)^2 + B(1+z)^2
Now put back into this line what A and B stood for and you will see that some cancelling can be done.