Thread: Simple algebra problem.

Hi there,

how do i solve for z? can someone help to show me step by step in how to solve for z?

100 = ( (7/ (1 + z)^1) + (107/ (1 + z)^2) )

Multiply each term (both sides) by (1+z)^2 You should get a quadratic equation (which in this case factorizes)

could you show me how to?

Let A and B be the 2 terms on the right hand side
So 100 = A+B Multiplying each term by (i+z)^2 we get 100(1+z)^2= A(1+z)^2 + B(1+z)^2

Now put back into this line what A and B stood for and you will see that some cancelling can be done.