The equation of a circle is x^2+6x+y^2-2y=12 ,what is the center ?
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You need to complete the square. I'll do the x bit $\displaystyle x^2+6x=(x+3)^2-9$
I forgot how to complete the square ,i will search that .
Aha so the answer should be (-3,1).
You got it.
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