The equation of a circle is x^2+6x+y^2-2y=12 ,what is the center ?

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- Apr 21st 2012, 10:07 AMMhmh96The center of circle
The equation of a circle is x^2+6x+y^2-2y=12 ,what is the center ?

- Apr 21st 2012, 10:15 AMa tutorRe: The center of circle
You need to complete the square. I'll do the x bit $\displaystyle x^2+6x=(x+3)^2-9$

- Apr 21st 2012, 10:18 AMMhmh96Re: The center of circle
I forgot how to complete the square ,i will search that .

- Apr 21st 2012, 10:43 AMMhmh96Re: The center of circle
Aha so the answer should be (-3,1).

- Apr 21st 2012, 10:50 AMa tutorRe: The center of circle
You got it.

(Clapping)