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Math Help - Uhg... I thought I did this last year -- basic algeblah

  1. #1
    Junior Member Melancholy's Avatar
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    Uhg... I thought I did this last year -- basic algeblah

    4 - 1/2a = 7/2 - a

    Could someone please work this for me? This is not the actual problem, but part of it, and I cannot remember what to do with the silly fractions next. There is something you do with the fractions... but my brain needs refreshing lol
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Melancholy View Post
    4 - 1/2a = 7/2 - a

    Could someone please work this for me? This is not the actual problem, but part of it, and I cannot remember what to do with the silly fractions next. There is something you do with the fractions... but my brain needs refreshing lol
    do you mean \frac {4 - 1}{2a} = \frac {7}{2 - a}? because that's not what you wrote
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  3. #3
    Junior Member Melancholy's Avatar
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    Ermm.... no.... I mean

    Four minus half of a = seven seconds minus a

    4 - [the fraction 1/2]a = [the fraction 7/2] - a

    Does that make sense? Sorry!
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Melancholy View Post
    Ermm.... no.... I mean

    Four minus half of a = seven seconds minus a

    4 - [the fraction 1/2]a = [the fraction 7/2] - a

    Does that make sense? Sorry!
    ok. first, get all the a's on one side and all the constants on the other:

    4 - \frac a2 = \frac 72 - a

    \Rightarrow a - \frac a2 = \frac 72 - 4 ........simplify each side

    \Rightarrow \frac a2 = - \frac 12 ...........multiply both sides by 2

    \Rightarrow a = -1


    This is my 4th post!!!!!
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  5. #5
    Junior Member Melancholy's Avatar
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    Thank you! And happy 4,000th post!!! Wow, that's a biiiiig step! On my forum, an admin just celebrated his 10,000th........ I know.... lol!

    Many more posts to come, my friend!
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